(a) Rs 142.40 Show
P = Rs 2000, r 1 = 4% p.a. for 1st year, r 2 = 3% p.a. for 2nd year \(\therefore\) A = P\(\big(1+\frac{r_1}{100}\big)\big(1+\frac{r_2}{100}\big)\) =2000\(\big(1+\frac{4}{100}\big)\big(1+\frac{3}{100}\big)\) =Rs\(\big(2000\times\frac{26}{25}\times\frac{103}{100}\big)\) = Rs 2142.40 \(\therefore\) C.I. = Rs 2142.40 – Rs 2000 = Rs 142.40. Answer Verified Hint: To solve this type of problem, first calculate the final amount needed to pay after two year then subtract this final amount to the given principal amount to calculate the compound interest in two years. Complete Step-by-step solution Hence the compound interest that needs to be paid after two year will be equal to Rs 205. Note: The interest rate for the first year in compound interest is the same as that in case of simple interest, Other than the first year, the interest compounded annually is always greater than that in case of simple interest. At what rate percent per annum will a sum of Rs. 2000 amount to Rs. 2205 in 2 years, compounded annually ?Answer Verified Hint: We have to only use the compound interest formula i.e. \[A = P{\left( {1 + \dfrac{R}{{100}}} \right)^T}\], where A is the amount after T years, P is the principal amount, R is the rate of interest and T is the time period.Complete step-by-step solution - As we know that the amount after two years will be equal to Rs. 2205. Note: Whenever we come up with this type of problem the we had to only use compound interest formula i.e. \[A = P{\left( {1 + \dfrac{R}{{100}}} \right)^T}\] And after that dividing both sides of the equation by p and then taking square root to both the sides and after that subtracting 1 from both sides and multiplying by hundred. We will get the required value of R (i.e. rate of interest at which principal amount is compounded annually). ML Aggarwal Solutions Class 9 Mathematics Solutions for Compound Interest Exercise 2.1 in Chapter 2 - Compound InterestQuestion 9 Compound Interest Exercise 2.1 Find the amount and the compound interest on ₹ 2000 at 10% p.a. for 2 years, compounded annually. Answer: Compound interest is calculated on the principal as well as the interest earned over the preceding month. It differs from simple interest in that interest is not applied to the principal when computing the next period's interest. It is given that Principal (P) = ₹ 2000 Rate of interest (r) = 10% p.a. Period (n) = 2 ½ years We know that Amount =\mathrm{P}(1+\mathrm{r} / 100)^{\mathrm{n}} Substituting the values =2000(1+10 / 100)^{2}(1+10 /(2 \times 100)) By further calculation = 2000 × 11/10 × 11/10 × 21/20 So we get = ₹ 2541 Here Interest = A – P Substituting the values = 2541 – 2000 = ₹ 541
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What is the compound interest on rupees 2000 for 2 years at 10% rate per annum?When the sum is compounded half-yearly, then the rate of interest becomes half and time becomes double. ∴ The compound interest is Rs. 205.
What is the compound interest on Rs 20000 for 2 years at the rate of 10 per annum compounded annually?Hence the compound interest that I need to pay after two year will be equal to Rs 4200.
What will be the compound interest on 2000 for 2 years?∴ The compound interest on Rs 2,000 for 2 years at 3% p.a. is Rs. 121.80.
What is the compound interest on Rs 2500 for 2 years at rate of interest 10% per annum?∴ Amount will be Rs. 3025 and Interest will be Rs. 525 If Compounded Annually.
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