It is given that
Principal = ₹ 8000
Rate of interest = 5% p.a.
We know that
Interest for the first year = Prt/100
Substituting the values
= (8000 × 5 × 1)/ 100
= ₹ 400
So the amount for the first year or principal for the second year = 8000 + 400 = ₹ 8400
Here
Interest for the second year = (8400 × 5 × 1)/ 100
So we get
= ₹ 420
We know that
Amount after the second year = 8400 + 420
= ₹ 8820
Total compound interest = 8820 + 8000
= ₹ 820
Principal = Rs. 8000
Time = 2 years
Rate = 5% for 1st year and 10% for 2nd year
\(\begin{array}{l} {\rm{A}} = 8000\left( {1 + \frac{5}{{100}}} \right)\left( {1 + \frac{{10}}{{100}}} \right)\\ \Rightarrow 8000 \times \frac{{21}}{{20}} \times \frac{{11}}{{10}} = {\rm{Rs}}.{\rm{\;}}9240 \end{array}\)
C.I = A – P = 9240 – 8000 = Rs. 1240
∴ Rs. 1240 is the compound interest earned.
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Related Find CI on a sum of rupees 8000 for 2 years at 5% per annum compounded annually?
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We have P = Rs 8000, R = 5% p.a., T = 2 years
Now, compound interest = A - P
= Rs 8820 - Rs 8000
= Rs 820
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Related Find CI on a sum of rupees 8000 for 2 years at 5% per annum compounded annually?
P = 8000
R = 5%
T = 2 years
A = P (1+ R/100)raise to n
A = 8000 ( 1+ 5/100) raise to 2
= 8000 (105 / 100)(105/ 100)
= 882,0
C.I = A - P
= 882,0 - 8000
= 820
Therefore C.I = 820
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- Reply(4)
820 is the correct answer
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- Reply
Related Find CI on a sum of rupees 8000 for 2 years at 5% per annum compounded annually?
P×r×t upon 100 is the formulae of simple interest .solve it
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