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Here, Principal (P) = Rs. 10000, Rate of Interest (R) = 10% = 5% (compounded half yearly) Time(n) = 1\ \frac{1}{2} years = 3 years (compounded half yearly) Amount (A) = P\left(1+\frac{R}{100}\right)^n = 10000\left(1+\frac{5}{100}\right)^3 = 10000\left(1+\frac{1}{20}\right)^3 = 10000\left(\frac{21}{20}\right)^3 = 10000\times\frac{21}{20}\times\frac{21}{20}\times\frac{21}{20} = Rs. 11,576.25 Compound Interest (C.I.) = A – P = Rs. 11,576.25 – Rs. 10,000 = Rs. 1,576.25 If it is compounded annually, then Here, Principal (P) = Rs. 10000, Rate of Interest (R) = 10%, Time (n) = 1\ \frac{1}{2} years. Amount (A) for 1 year = P\left(1+\frac{R}{100}\right)^n = 10000\left(1+\frac{10}{100}\right)^1 = 10000\left(1+\frac{1}{10}\right)^1 = 10000\left(\frac{11}{10}\right)^1 = 10000\times\frac{11}{10} = Rs. 11,000 Interest for \frac{1}{2} year = \frac{11000\times1\times10}{2\times100}=RS.\ 550 \therefore Total amount = Rs. 11,000 + Rs. 550 = Rs. 11,550 Now, C.I. = A – P = Rs. 11,550 – Rs. 10,000 = Rs. 1,550 Yes, interest Rs. 1,576.25 is more than Rs. 1,550. Complete Study Material based on Class 12th Syllabus, 10000+ Question Bank, Unlimited Chapter-Wise and Subject-Wise Mock Tests, Study Improvement Plan. ₹ 7999/- ₹ 4999/- Buy NowKnockout CUET (Physics, Chemistry and Biology)Complete Study Material based on Class 12th Syllabus, 10000+ Question Bank, Unlimited Chapter-Wise and Subject-Wise Mock Tests, Study Improvement Plan. ₹ 7999/- ₹ 4999/- Buy NowKnockout JEE Main (Six Month Subscription)- AI Coach Study Modules, - Unlimited Mock Tests, - Study Improvement Plan. ₹ 9999/- ₹ 8499/- Buy NowKnockout JEE Main (Nine Month Subscription)- AI Coach Study Modules, - Unlimited Mock Tests, - Study Improvement Plan. ₹ 13999/- ₹ 12499/- Buy NowKnockout NEET (Six Month Subscription)- AI Coach Study Modules, - Unlimited Mock Tests, - Study Improvement Plan. ₹ 9999/- ₹ 8499/- Buy NowSolution Here, (adsbygoogle = window.adsbygoogle || []).push({}); Principal (P)=Rs. 10000Rate of interest (R)=10% per annum compounded half yearly.⇒R=5% per half yearly Time (n)=112 years =3 half years Amount (A)=P(1+R100)n=10000(1+5100)3=10000(1+120)3=10000(2120)3=10000×2120×2120×2120 =Rs11,576.25 Compound Interest (C.I)=A−P=Rs 11,576.25−Rs 10,000⇒C.P=Rs. 1576.25So, Compound interest half yearly is Rs.1576.25---(1)Rate of interest (R)=10%Time (n)=1 years Amount (A) for 1 year A=P(1+R100)n (adsbygoogle = window.adsbygoogle || []).push({}); =10000(1+10100)1=10000(1+110)1=10000(1110)1=10000×1110=Rs.11,000 Interest for half year 12 year,=11000×1×102×100 [ ∵S.I=PTR100]=Rs.550Therefore, total amount =Rs. 11,000+Rs. 550=Rs.11,550 Now, C.I=A−P=Rs. 11,550−Rs.10000=Rs.1550So, Compound interest per annum is Rs.1550. ---(2) From (1) and (2), the interest Rs.1576.25 is more than Rs.1550.Hence, the answer is 'Yes'.What is the compound interest on a sum Rs 10000 at 12% per annum for 1 year and 4 months when the interest is compounded at every 8 months?1,664. ∴ The compound interest is Rs. 1,664.
What will be the compound interest on Rs 10000 at the rate of 12% per annum for a year compounded half yearly?=11872–10000=₹ 1872.
What is the compound interest on 20000 at 12%?20000 at 12% compound interest. Therefore, the answer of this question is Rs. 6000.
What is the simple interest of Rs 10000 for 12 months 10% pa?∴ The compound interest is the interest is compounded half-yearly will be ₹1025.
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