Given: Show
Sum of money becomes 6 times of itself in 15 years Formula used: (i) SI = PRT/100 Where, P = principal R = rate T = time (ii) A = SI + P Where, A = Amount SI = simple interest Calculation: Let the principal be P. For 15 years, SI = (P × R × 15)/100 ⇒ 15PR/100 A = SI + P ⇒ 6P = 15PR/100 + P ⇒ 5P = 15PR/100 ⇒ R = 500/15 ⇒ R = 100/3 ≈ 33.33% ∴ The rate of interest is 33.33%.  Let Principal be P So, Amount = 6P And, Interest = 6P – P ⇒ 5P Now, (P × R × 15)/100 = 5P ⇒ 3R/100 = 1 ⇒ 3R = 100 ⇒ R = 100/3 = 33.33% ∴ The rate of interest is 33.33%. A sum of money at simple interest becomes four times in 24 years. What is the rate of interest per annum? No worries! We‘ve got your back. Try BYJU‘S free classes today! Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses No worries! We‘ve got your back. Try BYJU‘S free classes today! No worries! We‘ve got your back. Try BYJU‘S free classes today! No worries! We‘ve got your back. Try BYJU‘S free classes today! Open in App Suggest Corrections4A sum of money becomes 4 / 3 of itself in 6 years at a certain rate of simple interest find the rate of interest. Open in App $$\eqalign{ & {1^{{\text{st}}}}\,{\text{Method}}: \cr & {\text{Let rate is }}R\% \cr & {\text{Now}}, \cr & P = 100, \cr & A = 400, \cr & I = 400 - 100 = 300, \cr & {\text{Time}},\,T = 10\,{\text{years}} \cr & I = \frac{{PTR}}{{100}} \cr & {\text{Or}},R = \frac{{ {100 \times I} }}{{PT}} \cr & {\text{Or}},R = \frac{{ {100 \times 300} }}{{ {100 \times 10} }} \cr & {\text{Hence}},{\kern 1pt} R = 30\% \cr} $$ 2nd Method : Here, the sum become 4 times that means 100, become 400. Rate of such question is given by $$R = \frac{{{\text{interest}}}}{{{\text{time}}}} = \frac{{300}}{{10}} = 30\% $$3rd Method : Here, 300% of rise in the sum so$$\eqalign{ & 100 - - - 300\% \uparrow - - - {\kern 1pt} 400; \cr & R = {\frac{{{\text{total}}\,{\text{percentage rise}}}}{{{\text{given time}}}}} \cr & \,\,\,\,\,\,\,\, = \frac{{300\% }}{{10}} \cr & \,\,\,\,\,\,\,\, = 30\% \cr} $$ The rate at which a sum becomes 4 times of itself in 16 years at simple interest is..... No worries! We‘ve got your back. Try BYJU‘S free classes today! No worries! We‘ve got your back. Try BYJU‘S free classes today! No worries! We‘ve got your back. Try BYJU‘S free classes today! Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses No worries! We‘ve got your back. Try BYJU‘S free classes today! Solution The correct option is C300/16%P×R×T100 = I4P = P+II = 3P 3P = P×R×16100R = 30016Home A sum of money becomes 4 / 3 of itself in 6 years at a certain rate of simple interest find the rate of interest. Open in App Solution Let the rate of interest is r and sum of money be x it becomes 4x3 in 6 yrsSo, SI in 6 yrs =4x3−x=x3As we know that SI =ptr100, where p=x, t=6. or x3=x×6×r100 or r=509 ∴r=5.56% (approx)So, rate of interest 5.56%Suggest Corrections 11 Similar questions Q. A sum of money becomes 6 times of itself in 8 years. Find the rate of Simple Interest. In what time does a sum of money becomes 4 times at the simple interest of 10% per annum?Detailed Solution
R % = [(4 - 1)× 100]/10 = 3 × 10 = 30%. ∴ Rate of interest is 30%.
At what rate percent per annum sum of money becomes 4 times of itself in 15 years?The rate at which a sum becomes four times of itself in 15 years at S.I., will be Amount = 20%.
At what rate of compound interest does a sum of money becomes 4 times of itself in 4 years?Hence at an interest rate of 100% , the sum of money becomes 4 times itself.
At which a sum becomes thrice of itself in 10 years at simple interest will be?∴ The rate of interest per annum is 20%.
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15 a sum of money becomes 4 times itself in 10 years at simple interest what is the rate of interest
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