- Aptitude
- Simple and compound interest
A) 4 % |
B) 6 % |
C) \( \Large 5\frac{2}{3} \)% |
D) \( \Large 6\frac{2}{3} \)% |
Correct Answer:
A) 4 % |
Description for Correct answer:
Let principal = 5 units
Hence interest =\( \Large 5 \times \frac{2}{5}=2 units \)
Time = 10 years,
By using formula,
Rate%
=\( \Large \frac{2}{5} \times \frac{100}{10}=4 \)%
Part of solved Simple and compound interest questions and answers : >> Aptitude >> Simple and compound interest
► MCQ Exam ON : Simple Interest
At what rate percent per annum will the simple interest on a sum of money be 2/5 of the amount in 10 years?
1) | 0.05 | |
2) | 0.04 | |
3) | 0.07 | |
4) | 0.06 | |
5) | NULL |
(Complaint Here As Incorrect)
Question Detail
- 1%
- 2%
- 3%
- 4%
Answer: Option D
Explanation:
Let sum = x
Time = 10 years.
S.I = 2x /5, [as per question]
Rate =( (100 * 2x) / (x*5*10))%
=> Rate = 4%
Similar Questions :
1. If A lends Rs. 3500 to B at 10% p.a. and B lends the same sum to C at 11.5% p.a., then the gain of B (in Rs.) in a period of 3 years is
- Rs. 154.50
- Rs. 155.50
- Rs. 156.50
- Rs. 157.50
Answer: Option D
Explanation:
We need to calculate
the profit of B.
It will be,
SI on the rate B lends - SI on the rate B gets
\begin{aligned}
\text{Gain of B}\\ &= \frac{3500\times11.5\times3}{100} - \frac{3500\times10\times3}{100}\\
= 157.50
\end{aligned}
2. What will the ratio of simple interest earned by certain amount at the same rate of interest for 6 years and that for 9 years.
- 1:2
- 2:1
- 2:2
- 2:3
Answer: Option D
Explanation:
Let the principal be P and rate be R
then
\begin{aligned}
\text{ratio = } [\frac{(\frac{P*R*6}{100})}{(\frac{P*R*9}{100})}] \\
= \frac{6PR}{9PR} = 2:3
\end{aligned}
3. At what rate percent per annum will the simple interest on a sum of money be 2/5 of the amount in 10 years
- 1%
- 2%
- 3%
- 4%
Answer: Option D
Explanation:
Let sum = x
Time = 10 years.
S.I = 2x /5, [as per question]
Rate =( (100 * 2x) / (x*5*10))%
=> Rate = 4%
4. Find the rate at Simple interest, at which a sum becomes four times of itself in 15 years.
- 10%
- 20%
- 30%
- 40%
Answer: Option B
Explanation:
Let sum be x and rate be r%
then, (x*r*15)/100 = 3x [important to note here is that simple interest will be 3x not 4x, beause 3x+x = 4x]
=> r = 20%
5. We have total amount Rs. 2379, now divide this amount in three parts so that their sum become equal after 2, 3 and 4 years respectively. If rate of interest is 5% per annum then first part will be ?
- 818
- 828
- 838
- 848
Answer: Option B
Explanation:
Lets assume that three parts are x, y and z.
Simple Interest, R =
5%
From question we can conclude that, x + interest (on x) for 2 years = y + interest (on y) for 3 years = z + interest (on y) for 4 years
\begin{aligned}
\left( x + \frac{x*5*2}{100} \right) = \left( y + \frac{y*5*3}{100} \right) = \left( z + \frac{z*5*4}{100} \right)\\
\left( x + \frac{x}{10} \right) = \left( y + \frac{3y}{20} \right) = \left( z + \frac{z}{5} \right) \\
=> \frac{11x}{10} = \frac{23y}{20} = \frac{6z}{5} \\
\text{lets assume k = }\frac{11x}{10} =
\frac{23y}{20} = \frac{6z}{5} \\
\text{then }x = \frac{10k}{11} \\
y = \frac{20k}{23}\\
z = \frac{5k}{6}\\
\text{we know x+y+z = 2379}\\
=> \frac{10k}{11} + \frac{20k}{23} + \frac{5k}{6} = 2379\\
\text{10k*23*6+20k*11*6+5k*11*23=2379*11*23*6}\\
\text{1380k+1320k+1265k=2379*11*23*6}\\
\text{3965k=2379*11*23*6}\\
k = \frac{2379*11*23*6}{3965}\\
\text{by putting value of k we can get x} \\
x = \frac{10k}{11} \\
=>x = \frac{10}{11}*\frac{2379*11*23*6}{3965}\\
=>x
= \frac{10*2379*23*6}{3965}\\
= \frac{2*2379*23*6}{793}\\
= 2 * 3 * 23 * 6 = 828
\end{aligned}
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