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Solution
Let, Principal amount be P.
Rate of interest be R per annum.
Time of investment is (T)=12 years.
Sum of the money becomes three times in 12 years.
⇒A=3P.
⇒A=P+(P×T×R100)
⇒3P=P(1+T×R100)
⇒3=1+12×R100
⇒3−1=12R100
⇒2=3R25
⇒50=3R
⇒503=R
Now, we need to find the number of years T such that, Sum of the money becomes five times.
⇒5P=P(1+T×R100)
⇒5=1+T×503×100
⇒5−1=T×13×2
⇒4=T6
⇒24=T
will it become 5
times at the same rate of simple interest 24 years.
How many years will a sum become 27 times when it trebles itself in 2 years at CI?
Hence amount will be 27 times in 6 years.
At what rate a sum of money will becomes eight times of itself in 3 years if the interest compounded yearly?
⇒R=100%
At what rate of compound interest does a sum of money becomes four times of itself in 4 year?
∴ Rate %=41.42% half yearly and 82.84% p.a.
On which rate does a certain amount will become four times of itself in two years if interest being calculated as compound interest?
Sum of money becomes 4 times after 2 years at CI. Calculations: Let the sum be P. ∴ The rate of interest is 100%.